Printing valid parantheses with letter Ruby

Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results.

Using Variables, Input/Output, Methods, Arithmetic

```def balancedpara(result, opencount, open, close)
    
    if open < opencount
       balancedpara(result + "(", opencount, open + 1, close)
    end
    if open > close
       balancedpara(result + ")", opencount, open, close + 1)
    end
    if close == opencount
       puts "[" + result + "]"
       return
    end
end
def main()
    puts "enter parantheses"
    inp = gets.chomp
    splited = inp.split('')
    open = 0
    close = 0
    opencount = splited.count('(')
    closecount = splited.count(')')
    #result = ""
    balancedpara("", opencount, 0, 0)
end
main()```

Explanation

Here we want to take input from user with parentheses and containing letter. Remove all invalid parentheses in order to make it valid, are return all possible outputs from it.

Code explanation

Here it count total number of open parentheses and based on that it perform other operations.But that is not the right way to do. Expected output is given below.

Expected Output

"Note: The input string may contain letters other than the parentheses ( and ). Example 1:

Input: ""()())()"" Output: [""()()()"", ""(())()""]

Example 2:

Input: ""(a)())()"" Output: [""(a)()()"", ""(a())()""]

Example 3:

Input: "")("" Output: [""""]"